-16x^2+4x+156=0

Solution for -16x^2+4x+156=0 equation:

-16x^2+4x+156=0

a = -16; b = 4; c = +156;
Δ = b2-4ac
Δ = 42-4·(-16)·156
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-100}{2*-16}=\frac{-104}{-32}
=3+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+100}{2*-16}=\frac{96}{-32}
=-3
$